If a variable line drawn through the intersection of the lines $\frac{x}{3} + \frac{y}{4} = 1$ and $\frac{x}{4} + \frac{y}{3} = 1$ meets the coordinate axes at $A$ and $B$ $(A \neq B)$,then the locus of the midpoint of $AB$ is

  • A
    $7xy = 6(x + y)$
  • B
    $4(x + y)^2 - 28(x + y) + 49 = 0$
  • C
    $6xy = 7(x + y)$
  • D
    $14(x + y)^2 - 97(x + y) + 168 = 0$

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